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Question

Solve the inequality: |4x+6|<30

A
6<x<6
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B
9<x<6
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C
10<x<6
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D
1<x<6
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Solution

The correct option is B 9<x<6
We know that if |a|<b, then a<b and a>b

Thus, |4x+6|<30 may be calculated as:

4x+6<30 and 4x+6>30

4x+6<30 and 4x>306

4x<24 and 4x>36

x<6 and x>9

That is 9<x<6.

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