Solve the inequality. Write the solution set in interval notation.
$| - 8 x + 9 | < 6$

(- \infty, - \frac{17}{8}) \cup (- \frac{5}{8}, \infty)

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(\frac{3}{8}, - \frac{15}{8})

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(\frac{3}{8}, \frac{15}{8})

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(- \infty, \frac{3}{8}) \cup (\frac{15}{8}, \infty)

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Solution

The correct option is D $(\frac{3}{8}, \frac{15}{8})$
$\Rightarrow - 6 < - 8 x + 9 < 6$

$\Rightarrow - 15 < - 8 x < - 3$

$\Rightarrow 3 < 8 x < 15$

$\Rightarrow \frac{3}{8} < x < \frac{15}{8}$

$∴ x \in (\frac{3}{8}, \frac{15}{8})$

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\frac{8}{x - 1} < 1

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Verify the following :

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Solve the inequality. Write the solution set in interval notation.|−8x+9|<6

The correct option is D (38,158)⇒−6<−8x+9<6⇒−15<−8x<−3⇒3<8x<15⇒38<x<158∴x∈(38,158)

Solve the inequality. Write the solution set in interval notation.
$| - 8 x + 9 | < 6$

The correct option is D $(\frac{3}{8}, \frac{15}{8})$
$\Rightarrow - 6 < - 8 x + 9 < 6$

$\Rightarrow - 15 < - 8 x < - 3$

$\Rightarrow 3 < 8 x < 15$

$\Rightarrow \frac{3}{8} < x < \frac{15}{8}$

$∴ x \in (\frac{3}{8}, \frac{15}{8})$