Solve the inequation:
3z−5≤z+3<5z−9; z∈R.
3<z<4
3<z≤4
3≤z<4
3≤z≤4
Given:
3z−5≤z+3<5z−9
⇒3z−5≤z+3 and z+3<5z−9
⇒2z≤8 and 4z>12
⇒z≤4 and z>3
Since its given that z∈R,
The range of inequation is 3<z≤4
Solve the inequation :
Graph the solution set on the number line.