Question

Solve the integral:$\int \frac{e^x-1}{e^x+1}dx$

Answer 1

$\int \frac{e^x-1}{e^x+1}dx$

$=\int \frac{e^x+1}{e^x+1}dx-\int \frac{2}{e^x+1}dx$
$=\int dx-2\int \frac{1}{e^x+1}dx$
$=x-2$