Solve the linear equation:
$15 (y - 4) - 2 (y - 9) + 5 (y + 6) = 0$

y = \frac{1}{7}

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y = \frac{3}{5}

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y = \frac{5}{2}

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y = \frac{2}{3}

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Solution

The correct option is D $y = \frac{2}{3}$
$W e h a v e, 15 (y - 4) - 2 (y - 9) + 5 (y + 6) = 0 ⟹ 15 y - 60 - 2 y + 18 + 5 y + 30 = 0 ⟹ 18 y - 12 = 0 ⟹ 18 y = 12 [T r a n s p o s i n g - 12 t o R H S] ⟹ y = \frac{12}{18} o r y = \frac{2}{3}$

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\frac{y + 7}{5} = \frac{2 y - x}{4} + 3 x - 5

\frac{7 - 5 x}{2} + \frac{3 - 4 y}{6} = 5 y - 18

15 (y - 4) - 2 (y - 9) + 5 (y + 6) = 0

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