Solve the linear equation:
$3 (t - 3) = 5 (2 t + 1)$

t = - 2

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t = 1

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t = 6

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t = - 9

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Solution

The correct option is A $t = - 2$
We have, $3 (t - 3) = 5 (2 t + 1)$
$\Rightarrow 3 t - 9 = 10 t + 5$
$\Rightarrow 3 t - 10 t = 5 + 9$ [Transposing 10t to LHS and -9 to RHS]
$\Rightarrow - 7 t = 14$
$\Rightarrow \frac{7 t}{7} = - \frac{14}{7}$
$\Rightarrow t = - 2$

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