Question

Solve the linear equation:
$15-6z=19-6z$.

• A. All real numbers
• B. $\frac{-2}{3}$
• C. An empty set
• D. $\frac{1}{3}$

Answer 1

The correct option is C An empty set

Given, $15-6z=19-6z$.

Cancelling $-6z$ from both sides, we get,

$⟹$ $15=19$.

Here, $LHS\ne RHS$.

That is, not a single value for$z$.

$\therefore$ It represents the empty set.

Therefore, option $C$ is correct.