The correct option is D x=7
Wehave,x+23−x−34=5−x−12⟹4(x+2)−3(x−3)12=10−x+12[TakingLCMonLHSandRHS]⟹4x+8−3x+912=11−x2⟹x+176=11−x1[Onmultiplyingbothsidesby2]⟹x+17=6(11−x)[Bycross−multiplication]⟹x+17=66−6x⟹x+6x=66−17[Transposing−6xtoLHSand17toRHS]⟹7x=49⟹x=7