wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the linear equation:

x2−15=x3+14

A
x=3.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=2.7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x=5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x=2.7
Given, x215=x3+14

The denominators on two sides are 2,3,4 and 5.

Their LCM is 60.

Multiplying both sides by 60, we get

60×(x215)=60×(x3+14)

60×x260×15=60×x3+60×14

30x12=20x+15

30x20x=15+12

10x=27

x=2710

x=2.7

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Identities for Irrational Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon