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Question

Solve the linear equations by cross multiplication method :

(a+b)x+(a−b)y=3a−b(2a2+b2)x−(a2−b)y=b2+2b

A

x=1 and y=3
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B

x=2 and y= 3
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C

x=1 and y= 2
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D

x=1 and y= 4
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Solution

The correct option is C
x=1 and y= 2
(a+b)x+(ab)y=3ab(2a2+b2)x(a2b)y=b2+2b

By cross multiplication method :


x(ab)(b2+2b)(3ab)(a2+b)=y(3ab)(2a2+b2)(b2+2b)(a+b)=1(a+b)(a2b)(2a2+b2)(ab)x3a3b3+ab2a2bb2ab=y6a22b3+2ab22ab22a2b2b22ab=1(3a3b3+ab2a2bb2ab)x(3a3b3+ab2a2bb2ab)=1(3a3b3+ab2a2bb2ab)y2(3a3b3+ab2a2bb2ab)=1(3a3b3+ab2a2bb2ab)x=y2=1x=1,y=2

So, option c is correct.

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