Question

Solve the logarithmic equation rounding to the nearest ten-thousandth
$3\log 2x=4$

Answer 1

Finding the value of $x$ of logarithmic equation:

Given $3\log 2x=4$

$$\begin{gathered} \therefore 3\log 2x=4 \\ \Rightarrow \log 2x=\frac{4}{3} \end{gathered}$$
$\Rightarrow 2x={10}^{\frac{4}{3}}$ ( Taking $\log$ base $10$)
$$\begin{gathered} \Rightarrow 2x={10}^{1.33} \\ \Rightarrow x=10.77217.. \end{gathered}$$
Hence the required answer is $10.77217$.