Question

Solve the pair of equations by Elimination method.
$2x+y-5=0,3x-2y-4=0$

Answer 1

Given:

$2x+y-5=0$ $..........\left(1\right)$

$3x-2y-4=0$ $..........\left(2\right)$

On multiplying equation $\left(1\right)$ by $2$ and adding with equation $\left(2\right)$, we get

$4x+2y-10=0$

$\frac{3x-2y-4=0}{7x-14=0}$

$7x=14$

$x=2$

Now putting value of $x=2$ in eqn. $\left(1\right)$, we get

or, $2\times 2+y-5=0$

or, $4+y-5=0$

or, $y-1=0$

or, $y=1$

So, $x=2$ and $y=1$