Solve the pair of equations using method of substitution.
2x+3y = 13 , 4x-y = 5 [2 MARKS]

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Solution

Concept : 1 Mark
Calculation : 1 Mark

Given equations are,

$2 x + 3 y = 13 \dots \dots (i)$

$4 x - y = 5 \dots \dots (i i)$

Consider,

$4 x - y = 5$

$y = 4 x - 5$

Substituting $y$ in $(i)$ we get,

$2 x + 3 y = 13$

$2 x + 12 x - 15 = 13$

$14 x = 28$

$\Rightarrow x = 2$

$∴ y = 8 - 5 = 3$

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x + y - 5 = 0, y - 2 x = 2 x

2 x + y = 5

2 x - 3 y = 3

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x + 3 y = 8$

$2 x = 2 + 3 y$

2 x + 3 y = 9

3 x + 4 y = 5

x + y = 5

2 x - 3 y = 4

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