Solve the pair of equations using the method of substitution 3x-y = 8 ,5x+y = 0 [2 MARKS]

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Solution

Concept : 1 Mark
Calculation : 1 Mark

Given equations are,

$3 x - y = 8 \dots \dots (i)$

$5 x + y = 0 \dots \dots (i i)$

Consider,

$5 x + y = 0$

$\Rightarrow y = - 5 x$

Substituting for $y$ in $(i)$ , we get

$3 x - (- 5 x) = 8$

$8 x = 8$

$\Rightarrow x = 1$

$∴ x = 1, y = - 5$

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3 x - y - 2 = 0

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\frac{5 y}{2} - \frac{x}{3} = 8

\frac{y}{2} + \frac{5 x}{3} = 12

x + \frac{6}{y} = 6

3 x - \frac{8}{y} = 5

Solve the following pairs of linear (simultaneous) equations using method of elimination by substitution:

$2 x + 3 y = 8$

$2 x = 2 + 3 y$

3 x + y + 1 = 0

3 x - 4 y = 10

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