Solve the pair of linear equations $2 x + 3 y = 11$ and $2 x - 4 y = - 24$ .

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Solution

The pair of linear equations is given as,

$2 x + 3 y = 11 \dots (i)$

$2 x - 4 y = - 24 \dots (i i)$

Subtracting equation $(i i)$ from equation $(i),$

$(2 x + 3 y) - (2 x - 4 y) = 11 - (- 24)$
$\Rightarrow 7 y = 35$

$\Rightarrow y = 5$

Substitute the value of $y$ in equation $(i),$

$2 x + 3 (5) = 11$

$\Rightarrow 2 x + 15 = 11$
$\Rightarrow 2 x = - 4$
$\Rightarrow x = - 2$

Therefore, the values are $x = - 2$ and $y = 5$ .

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Similar questions

2 x + 3 y = 11

2 x - 4 y = - 24

2 x + 3 y = 11

2 x - 4 y = - 24

Solve the following system of equations by substitution method:

2x+3y=11
2x−4y=−24

6 x + 3 y = 6 x y, 2 x + 4 y = 5 x y

\begin{matrix} \frac{2}{x} + \frac{3}{y} = 13 \frac{5}{x} - \frac{4}{y} = - 2 \end{matrix}

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