Solve the pair of linear equations by substituting method:-

√2x+√3y=0

√3x-√8y=0

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Solution

√2x+√3y= 0
√2x= -√3y
x=-√(3/2)y
put the vale of x in equation
√3x-√8y=0
-√(3×3/2)-√8y =0
-3y/√2 - √8y =0
-3y - √(8×2)y =0
-3y-4y = 0
-7y = 0
y = 0
x=0

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(P . S)

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