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Question

Solve the pair of linear equations by using cross multiplication method
(iii) (ab)x+(a+b)y=2a22ab2, (a+b)(x+y)=4ab

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Solution

(ab)x+(a+b)y=2a22ab2
(a+b)x+(a+b)y=4ab
x4ab(a+b)(a+b)(2a22ab2)=y(a+b)(2a22ab2)4ab(ab)=1a2b2a2b22ab
x(a+b)(4ab2a2+2ab2)=12b22ab and y2a(a+b)(ab2)4ab(ab)=12b22ab
x=(a+b)(4ab2a2+2ab2)2b(b+a) and y=2a(a+b)(ab2)4ab(ab)2b(b+a)
x=4ab2a2+2ab22b and y=a(a+b)(ab2)2ab(ab)b(b+a)
x=2ab+a2ab2b and y=a(a+b)(ab2)2ab(ab)b(b+a)

1508998_1177955_ans_c2d3fc44348a463d9524a45c4b25465c.PNG

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