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Question

Solve the polynomial equation
9x24z224xy+16y2+20y15x+10

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Solution

9x24z224xy+16y2+20y15x+10=0

9x2(24y+15)x4z2+16y2+20y+10=0

x1,2=b±b24ac2a

x=(24y15)±(24y15)249(4z2+16y2+20y+10)29

x=8y±16z215+56

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