Solve the previous problem if the paperweight is inverted at its place so that the spherical surface touches the paper.

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Solution

Given,
Taking the radius of the paperweight as its thickness = 3 cm
Refractive index of the paperweight (μ_g) = 3/2
Refractive index of the air (μ₁) = 1

Image shift is given by:
$∆ t = (1 - \frac{1}{μ}) t = (1 - \frac{2}{3}) 3 = (\frac{1}{3}) 3 = 1 cm$

The upper surface of the paperweight is flat and the spherical spherical surface is in contact with the printed letter.
Therefore, we will take it as a simple refraction problem.

Hence, the image will appear 1 cm above point A.

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