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Existence of Limit

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Solve the problem $6 C_{2}$

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Solution

$^{6} C_{2}$

$^{n} C_{r} = \frac{n!}{(n - r!) r!} = \frac{6!}{(6 - 2)! (2)!} = \frac{6!}{4! 2!}$

$\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1 \times 2 \times 1} = 15$

$^{6} C_{2} = 15$

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