Question

Solve the problem:-
$\frac{3x-1}{{\left(x+2\right)}^2}=1$

Answer 1

$\frac{3x-1}{{(x+2)}^2}=1$

$\Rightarrow {(x+2)}^2=3x-1$

$\Rightarrow x^2+4x+4-3x+1=0$

$\Rightarrow x^2+x+5=0$

$\Rightarrow x=\frac{-1\pm \sqrt{1-4\times 1\times 5}}{2\times 1}$

$\therefore x=\frac{-1\pm \sqrt{-19}}{2}$

or $x=\frac{-1\pm i\sqrt{19}}{2}$