Question

Solve the problem:

Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities In jogging (a) from A to B and

(b) from A to C ?

Answer 1

Velocity = dispacement / time
Speed = distance / time

a) when he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 s

velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s

b)when he jogs from A to B and turns back to C,
displacement = 300-100 = 200m
distance = 300+100 = 400m
time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s