Question

Solve the quadratic by factorization:-
$64x^2-9=0$

Answer 1

Consider the given equation.

$64x^2-9=0$

${\left(8x\right)}^2-3^2=0$

$(8x-3)(8x+3)=0$

$(8x+3)=0$

$x=-\frac{3}{8}$

And

$(8x-3)=0$

$x=\frac{3}{8}$

Hence, this is the required answer.