Question

Solve the quadratic equation $3x^2+5x+2=0$ using formula method.

Answer 1

Given, $3x^2+5x+2=0$
On comparing this equation with $a{x}^2+bx+c=0$, we get $a=3,b=5$ and $c=2$
Now, $b^2-4ac={\left(5\right)}^2-4\times 3\times 2$
$=25=24$
$=1$
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
$==\frac{-5\pm \sqrt{1}}{2\times 3}$
$=\frac{-5\pm 1}{6}$
$x=\frac{-5+1}{6}$
$x=\frac{-5-1}{6}$
$\therefore$ $\frac{-2}{3}$ and $-1$ are the roots of the given quadratic equation.