wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the quadratic equation 3x413x2+10=0.

Open in App
Solution

The given quadratic equation is,
3x413x2+10=0
3(x2)213(x2)+10=0
Substituting x2=m we get
3m213m+10=0
3m23m10m+10=0
3m(m1)10(m1)=0
(m1)(3m10)=0
m1=0 or 3m10=0
m=1 or 3m=10
m=1 or m=103
Substituting m=x2, we get
x2=1 or x2=103
x=±1 or x=±103
x=1,1,103,103
1,1,103 and 103 are the roots of the given quadratic equation.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon