Question

Solve the quadratic equation :$4x^2+4bx-(a^2-b^2)=0$

Answer 1

$4x^2+4bx-(a^2-b^2)=0$

$⟹4x^2+4bx+b^2=a^2$

$⟹(2x+b{)}^2=a^2$

$⟹2x+b=\pm a$

$⟹2x=b\pm a$

$⟹Rootsofgivenquadraticequationare:$

$x_1=\frac{a+b}{2},x_2=\frac{b-a}{2}$