Question

Solve the quadratic equation $x^2-7x-5=0$

Answer 1

Comparing the given equation with $a{x}^2+bx+c=0$ we find that a = 1, b = -7 and c = -5
D = ${(-7)}^2-4\times 1\times (-5)=49+20=69>0$
Since D is positive the equation has two roots given by $\frac{7+\sqrt{69}}{2},\frac{7-\sqrt{69}}{2}$
$\Rightarrow x=\frac{7+\sqrt{69}}{2},\frac{7-\sqrt{69}}{2}$ are the required solutions