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Question

Solve the Quadratic Equation for x
453x2+5x23=0

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Solution

Given,

453x2+5x23=0

a=453,b=5,c=23

x1,2=b±b24ac2a

x1=5+524453(23)2453=5+25+36243906

x2=5524453(23)2453=525+36243906

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