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Question

Solve the quadratic equation :(m2+m)(m2+m3)=28

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Solution

Let m2+m=k
k(k3)=28
k23k28=0
(k7)(k+4)=0
If k7=0:
m2+m7=0
m=1±292
If k+4=0:
m2+m+4=0
The above has no real solutions as discriminant is negative.
Therefore, final solution:
m=1±292

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