Question

Solve the quadratic equation $x^2+5x+6=0$.

Answer 1

Given : $x^2+5x+6=0$

$$\begin{gathered} \Rightarrow x^2+2x+3x+6=0 \\ \Rightarrow x(x+2)+3(x+2)=0 \\ \Rightarrow (x+2)(x+3)=0 \\ \text{Either}x+2=0\text{or}x+3=0 \\ \Rightarrow x=-2\text{or}x=-3 \end{gathered}$$

Hence, $x=-2\text{or}x=-3$ is the solution of the given quadratic equation.