Question

Solve the quadratic equation $y^2-64=0$.

Answer 1

Given equation is
$y^2-64=0$
$\Rightarrow {\left(y\right)}^2-{\left(8\right)}^2=0$
$\Rightarrow (y+8)(y-8)=0$
$\Rightarrow y+8=0$ or $y-8=0$
$\Rightarrow y=-8$ or $y=8$
Hence, $y=-8,8$ are the roots of the given quadratic equation.