Question

Solve the quadratic equations by factorization:-
$y^2+2\sqrt{3}y+3=0$.

Answer 1

$y^2+2\sqrt{3}y+3=0$

$\Rightarrow$ $y^2+\sqrt{3}y+\sqrt{3}y+3=0$

$\Rightarrow$ $y(y+\sqrt{3})+\sqrt{3}(y+\sqrt{3})=0$

$\Rightarrow$ $(y+\sqrt{3})(y+\sqrt{3})=0$

$\therefore$ $y=-\sqrt{3}$ and $y=-\sqrt{3}$