Solve the system : $6 x + 5 y = - 3, y = - 2 x - 7$

(- 2, 4)

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(- 1, 2)

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(- 8, 9)

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(- 7, 8)

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Solution

The correct option is C $(- 8, 9)$
$6 x + 5 y = - 3$ ....... (1)
$y = - 2 x - 7$ .......(2)
Because the second equation is of the form y equals, let's use the substitution method. From the second equation we can substitute $- 2 x - 7$ for $y$ in the first equation $6 x + 5 y = - 3$
i.e., $6 x + 5 (- 2 x - 7) = - 3$
Solving this equation yields
$6 x - 10 x - 35 = - 3$
$- 4 x - 35 = - 3$
$- 4 x = 32 \Rightarrow x = - 8$
Substitute -8 for x in the second equation to yield.
$y = - 2 (- 8) - 7 = 16 - 7 = 9$
The solution set is $(- 8, 9)$

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