Solve the system of equations
$2 x + 5 y = 1$
$3 x + 2 y = 7$ .

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Solution

Consider the given equations.
$2 x + 5 y = 1 . . . . (1)$
$3 x + 2 y = 7 . . . . (2)$

On multiply by $(1)$ by $2$ and $(2)$ by $5$ , we get:
$4 x + 10 y = 2 . . . . (3)$
$15 - x + - 10 y = - 35 - -------------- - . . . . (4)$
$- 11 x = - 33$ [Subtracting $(4)$ from $(3)$ ]

$\Rightarrow x = 3$

Putting $x = 3$ in $(1)$ , we get:
$2 \times 3 + 5 y = 1$

$\Rightarrow 6 + 5 y = 1$

$\Rightarrow 5 y = - 5$

$\Rightarrow y = - 1$

Hence, $x = 3, y = - 1$ is the solution of the given system of linear equations.

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