Solve the system of equations 3x – 2y + 3z = 8, 2x + y – z = 1 and 4x – 3y + 2z = 4 by matrix method.

Open in App

Solution

The matrix form is

AX = B

A = $⎡ ⎢ ⎣ \begin{matrix} 3 & - 2 & 3 2 & 1 & - 1 4 & - 3 & 2 \end{matrix} ⎤ ⎥ ⎦$ , X = $⎡ ⎢ ⎣ \begin{matrix} x y z \end{matrix} ⎤ ⎥ ⎦$ , B = $⎡ ⎢ ⎣ \begin{matrix} 814 \end{matrix} ⎤ ⎥ ⎦$
Premultiplying both sides by

$A^{- 1}$ so that X can be given by $A^{- 1}$ B

Suggest Corrections

Similar questions

3 x - 2 y + 3 z = 8

2 x + y - z = 1

4 x - 3 y + 2 z = 4

2 x + 3 y + 3 z = 5, x - 2 y + z = - 4, 3 x - y - 2 z = 3

2 x + 3 y + 3 z = 5

x - 2 y + z = - 4

3 x - y - 2 z = 3

2 x + 3 y + 3 z = 5

x - 2 y + z = 4

3 x - y - 2 z = 3

Solve system of linear equations, using matrix method.

2x + 3y + 3z = 5

x − 2y + z = −4

3x − y − 2z = 3

Join BYJU'S Learning Program