Question

Solve the system of equations
$\frac{bx}{a}-\frac{ay}{b}+a+b=0$
and $bx-ay+2ab=0$

• A. $x=-a$; $y=b$
• B. $x=a$; $y=b$
• C. $x=-a$; $y=-b$
• D. None of these

Answer 1

Answer: (A)

$x=-a$; $y=b$

$\frac{bx}{a}-\frac{ay}{b}+a+b=0$ _____ (1)

$bx-ay+2ab=0$ _______ (2)

$\left[\right(1)-\frac{\left(2\right)}{b}]$ we get

$\Rightarrow (\frac{-a}{b}+1)y+(a+b-2b)=0$

$\Rightarrow \left(\frac{-a+b}{b}\right)y=(-a+b)$

$y=b$

On substituting $y$in equ (1)

$\frac{bx}{a}-\frac{ab}{b}+a+b=0$

$\Rightarrow \frac{x}{a}=-1\Rightarrow x=-a$