Question

Solve the system of equations: $x-2y=0,3x+4y=20$

Answer 1

The given equations are as follows:
x − 2y = 0 ....(i)
3x + 4y = 20 ....(ii)
On multiplying (i) by 2, we get:
2x − 4y = 0 ....(iii)
On adding (ii) and (iii), we get:
5x = 20 ⇒ x = 4
On substituting x = 4 in (i), we get:
4 − 2y = 0 ⇒ 4 = 2y ⇒ y = 2
Hence, the required solution is x = 4 and y = 2.