Question

Solve the system of in equations
$\frac{x}{2x+1}\ge \frac{1}{4};\frac{6x}{4x-1}<\frac{1}{2}$

Answer 1

$\begin{array}{c}\frac{x}{2x+1}\ge \frac{1}{4};\frac{6x}{4x-1}<\frac{1}{2}\\ 4x\ge 2x+1;12x<4x-1\\ 2x\ge 1;8x<1\\ x\ge \frac{1}{2};x<8\\ So,\\ \frac{1}{2}\le x<8\end{array}$