Question

Solve the system of inequalities: $-2<1-3x<7$

• A. $-2<x<1$
• B. $-2<x<2$
• C. $-1<x<1$
• D. $-2<x<-1$

Answer 1

Answer: (A)

$-2<x<1$

Given inequality is $-2<1-3x<7$
Multiplying by -ve sign or $-1$ (inequality gets reversed)
$2>3x-1>-7$
Adding $1$, we get
$3>3x>-6$
$1>x>-2$ or
$-2<x<1$
Hence, answer is option A.