Solve the trignometric equation and find ALL solutions f(x)=2cosx+1=0
A
π3+2nπ,5π3+2nπ
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B
−1/2
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C
no solutions
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D
2π3+2nπ,4π3+2nπ
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Solution
The correct option is D2π3+2nπ,4π3+2nπ f(x)=2cosx+1=0 2cosx=−1 cosx=−12 Value of cosx is negative in 2nd and 3rd quadrant cos(π−π3)=cos(2π3)=−12 cos(π+π3)=cos(4π3)=−12 x=2π3+2nπ,4π3+2nπ