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Question

Solve them by the method of elimination. In an A.P, Sn=5n2+11n, find Tn.

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Solution

Sn=5n2+11n
Sn1=5(n1)2+11(n1)
Tn=SnSn1
=5n2+11n5(n1)211(n1)
=5(n2(n1)2)+11(nn+1)
=5[(nn+1)(n+n1)]+11
=5(2n1)+11
=10n5+11
=10n+6

1218722_1370218_ans_a8f31812e9564587b52f49eb49a996fe.PNG

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