Solve this: $3 x^{2} + 2 y^{2} = 0, 4 x^{- 2} + 6 y = 5$

Open in App

Solution

$3 x^{2} + 2 y^{2} = 0 ⟹ x = 0, y = 0$
$4 x^{- 2} + 6 y = 5 ⟹ x \neq 0$
From the above equation $x, y$ has no solutions

Suggest Corrections

Similar questions

3 x^{2} - 2 y^{2} + 5 z^{2} = 0, 7 x^{2} - 3 y^{2} - 15 z^{2} = 0, 5 x - 4 y + 7 z = 6.

2 x^{2} + 2 y^{2} + 3 x + 6 y - 5 = 0

3 x^{2} + 3 y^{2} - 7 x + 8 y - 11 = 0

2 y^{2} + 6 y = 3

2 y^{2} - 4 x y + 3 x^{2} = 17, y^{2} - x^{2} = 16

3 x^{2} - 2 y^{2} + 4 x - 6 y = 0

y = 2 x

Join BYJU'S Learning Program