Solve this-20- nbsp- Areas of a square and a rectangle are equal- If the dimensions of the rectangle are nbsp-200 nbsp-units and nbsp-50 nbsp-units respectively- then find the length of one side of the square-

Dear Student, Given: #8201;Area #160;of #160;square #160;= #160; #160;Area #160;of #160;rectangleArea #160;of #160;rectangle #160;= #16 ...

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Standard VII

Mathematics

Area of Rectangle

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Question

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20. Areas of a square and a rectangle are equal. If the dimensions of the rectangle are $\sqrt{200}$ units and $\sqrt{50}$ units respectively, then find the length of one side of the square?

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Solution

Dear Student,

$G i v e n : A r e a o f s q u a r e = A r e a o f r e c \tan g l e A r e a o f r e c \tan g l e = \sqrt{200} \times \sqrt{50} A r e a o f S q u a r e = {(S i d e)}^{2} H e n c e, {(S i d e)}^{2} = \sqrt{200} \times \sqrt{50} S i d e^{2} = \sqrt{200 \times 50} S i d e^{2} = \sqrt{10, 000} S i d e^{2} = 100 S i d e = \sqrt{100} = 10 u n i t . H e n c e, t h e s i d e o f s q u a r e i s 10 u n i t s .$

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Solve this: 20. Areas of a square and a rectangle are equal. If the dimensions of the rectangle are 200 units and 50 units respectively, then find the length of one side of the square?

Dear Student, Given: Area of square = Area of rectangleArea of rectangle = 200×50Area of Square = Side2Hence, Side2 = 200×50Side2 = 200×50Side2 = 10,000Side2 = 100Side = 100 = 10 unit.Hence, the side of square is 10 units. Regards

Solve this:

20. Areas of a square and a rectangle are equal. If the dimensions of the rectangle are $\sqrt{200}$ units and $\sqrt{50}$ units respectively, then find the length of one side of the square?