Solve this-A man hears his echo from a nearby hill 2s after nbsp-he shouted- If the frequency of his voice is 260 nbsp-Hz and the wavelength is 1-29m- how far away is nbsp-the hill- nbsp-

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Byju's Answer

Standard IX

Physics

Applications of Reflection of Sound

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A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260 Hz and the wavelength is 1.29m, how far away is the hill?

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Solution

$D e a r s t u d e n t g i v e n t h a t t h e f r e q u e n c y o f v o i c e i s = 260 h z a n d w a v e l e n g t h o f v o i c e = 1.29 m n o w v e l o c i t y o f w a v e = v = w a v e l e n g t h \times f r e q u e n c y \Rightarrow v = 260 * 1.29 \Rightarrow v = 335.4 m / s n o w g i v e n t i m e a f t e r w h i c h m a n h e a r s e c h o = 2 s e c o n d l e t t h e d i s \tan c e o f h i l l f r o m m a n b e x m e t e r s t h e d i s \tan c e t r a v e l l e d b y w a v e i n 2 s e c = 2 x (a s t h e w a v e p r o p a g a t e s a w a y f r o m m a n t o t h e h i l l a n d b a c k t o h i m a s h e a r s t h e e c h o, s o d i s \tan c e t r a v e l l e d b y w a v e b e c o m e s 2 x) v = \frac{2 x}{2} (a s v e l o c i t y = d i s \tan c e / t i m e) 335.4 = \frac{2 x}{2} t h e r e f o r e d i s \tan c e b e t w e e n t h e m a n a n d h i l l i s 335.4 m . R e g a r d s$

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Solve this: A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260 Hz and the wavelength is 1.29m, how far away is the hill?

Solve this:

A man hears his echo from a nearby hill 2s after he shouted. If the frequency of his voice is 260 Hz and the wavelength is 1.29m, how far away is the hill?