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Byju's Answer
Standard XII
Mathematics
Existence of Limit
Solve this: ...
Question
Solve this:
21
.
I
f
α
,
β
a
r
e
t
h
e
r
o
o
t
s
o
f
t
h
e
e
q
u
a
t
i
o
n
x
2
-
p
x
+
q
=
0
,
t
h
e
n
f
i
n
d
t
h
e
q
u
a
d
r
a
t
i
c
e
q
u
a
t
i
o
n
t
h
e
r
o
o
t
s
o
f
w
h
i
c
h
a
r
e
α
2
-
β
2
α
3
-
β
3
a
n
d
α
3
β
2
+
α
2
β
3
.
Open in App
Solution
Dear student
Given
:
α
and
β
are
roots
of
x
2
-
px
+
q
=
0
α
+
β
=
-
coeff
.
of
x
coeff
.
of
x
2
=
-
-
p
1
=
p
αβ
=
constant
term
coeff
.
of
x
2
=
q
1
=
q
We
know
that
α
+
β
2
=
α
2
+
β
2
+
2
αβ
α
2
+
β
2
=
p
2
-
2
q
and
α
-
β
2
=
α
2
+
β
2
-
2
αβ
=
p
2
-
2
q
-
2
q
=
p
2
-
4
q
So
,
α
-
β
=
±
p
2
-
4
q
We
want
to
find
the
quadratic
equation
whose
roots
are
:
α
2
-
β
2
α
3
-
β
3
and
α
3
β
2
+
α
2
β
3
let
S
and
P
be
the
sum
and
product
of
roots
respectively
.
S
=
α
2
-
β
2
+
α
3
-
β
3
+
α
3
β
2
+
α
2
β
3
S
=
α
+
β
α
-
β
+
α
-
β
α
2
+
β
2
+
αβ
+
α
2
β
2
α
+
β
Case
I
when
α
-
β
=
p
2
-
4
q
S
=
p
×
p
2
-
4
q
+
p
2
-
4
q
p
2
-
2
q
+
q
+
q
2
p
=
p
p
2
-
4
q
+
p
2
-
4
q
p
2
-
2
q
+
q
+
q
2
p
=
p
2
-
4
q
p
+
p
2
-
q
+
pq
2
and
P
=
α
2
-
β
2
α
3
-
β
3
α
2
β
2
α
+
β
=
α
+
β
α
-
β
α
-
β
α
2
+
β
2
+
αβ
α
2
β
2
α
+
β
=
p
p
2
-
4
q
p
2
-
q
q
2
p
=
p
2
q
2
p
2
-
4
q
p
2
-
q
So
,
required
polynomial
is
=
x
2
-
Sx
+
P
=
x
2
-
p
2
-
4
q
p
+
p
2
-
q
+
pq
2
x
+
p
2
q
2
p
2
-
4
q
p
2
-
q
Similarly
try
when
α
-
β
=
-
p
2
-
4
q
Regards
Suggest Corrections
0
Similar questions
Q.
If
α
,
β
are the roots of
x
2
−
p
x
+
q
=
0
, then the product of the roots of the quadratic equation whose roots are
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β
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and
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q
x
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Q.
If
α
,
β
are the roots of
x
2
−
p
x
+
q
=
0
, find the value of
(1)
α
2
+
β
2
(2)
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3
+
β
3
Q.
If
α
,
β
are the roots of the equation
x
2
−
p
x
+
q
=
0
, then the quadratic equation whose roots are
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2
−
β
2
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α
3
−
β
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β
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+
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2
β
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:
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