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Q.15. Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference of the digits is 3, determine the number.

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Solution

Dear student,

$L e t t h e u n i t' s d i g i t b e' y' a n d t e n s d i g i t' s b e' x' ∴ 2 - d i g i t N u m b e r = 10 T + U = 10 x + y w h e n t h e d i g i t s g e t r e v e r s e d N u m b e r = 10 y + x A c c . t o q u e s t i o n, 7 (10 x + y) = 4 (10 y + x) 70 x + 7 y = 40 y + 4 x 70 x - 4 x = 40 y - 7 y 66 x = 33 y 66 x - 33 y = 0 2 x - y = 0 - - (1) a l s o g i v e n y - x = 3 - - (2) - - [c o n s i d e r i n g y > x] f r o m (1) a n d (2) 2 x - y = 0 - x + y = 3 x = 3 p u t x = 3 i n (2) y - 3 = 3 \Rightarrow y = 6 T h e r e f o r e, r e q u i r e d n o . = 10 (3) + 6 = 30 + 6 = 36$

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Solve this: Q.15. Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference of the digits is 3, determine the number.

Solve this:
Q.15. Seven times a two digit number is equal to four times the number obtained by reversing the order of its digits. If the difference of the digits is 3, determine the number.