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Q.150. If the position vectors of three points are a-2b+3c, 2a+3b-4c and -7a+10c, then the three points are
(a) collinear
(b) non-collinear
(c) coplanar
(d) None of these

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Solution

Let poistion vector of Pp=a-2b+3cQq=2a+3b-4cRr=-7a+10cLet us first assume that these points are collinear. Then PQR lie in a striaght line.Veector PQ must be parallel to QR PQ=q-p=2a+3b-4c-a-2b+3c=a+5b-7c QR=r-q=-7a+10c-2a+3b-4c=-9a-3b-14cPQ doesn't looks parallel to QR. Hence we cannot say they are collinear.Also we cannot commenthat they are non-collinear as a, b and c might take values such that PQ becomes parallel to PR. Since we dont know a, b and c hence we cannot commmentBut we know any three points always lie on a plane. So we can definitely say that they are co-planar.

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