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Structure of Glucose

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Q.5. 32 % methyl alcohol (w/w) [Aqueous solution]. Find mole fraction of methyl alcohol.

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Solution

$32 % m e t h y l a l c o h o l m e a n s 32 g m e t h a n o l i n 100 g s o l u t i o n . S o w e i g h t o f m e t h a n o l = 32 g W e i g h t o f w a t e r = 68 g M o l e s o f m e t h a n o l n_{2} = \frac{32}{32} = 1 M o l e s o f w a t e r n_{1} = \frac{68}{18} = 3.78 M o l e f r a c t i o n o f m e t h a n o l X_{2} = \frac{n_{2}}{n_{1} + n_{2}} = \frac{1}{3.78 + 1} = \frac{1}{4.78} = 0.2092$

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