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Byju's Answer
Standard VII
Mathematics
Rearranging the Terms in an Inequation
Solve this Q...
Question
Solve this
Q.(5). 4m + 6n = 54 ; 3m + 2n = 28
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Solution
Dear student
4
m
+
6
n
=
54
.
.
.
1
3
m
+
2
n
=
28
.
.
.
2
Multiply
equation
2
by
3
,
we
get
9
m
+
6
n
=
84
.
.
.
3
Subtracting
equation
3
from
1
we
get
⇒
4
m
+
6
n
-
9
m
-
6
n
=
54
-
84
⇒
-
5
m
=
-
30
m
=
6
Putting
m
=
6
in
equation
2
,
we
get
⇒
3
6
+
2
n
=
28
⇒
2
n
=
28
-
18
⇒
2
n
=
10
n
=
5
Regards
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Rearranging the Terms in an Inequation
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