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Q.6. Write the balanced chemical equations for the following reactions.
(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogen carbonate
(b) Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.
(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide ( $C u_{2} I_{2} / C u I$ ), liberates iodine gas and also forms potassium sulphate.

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Solution

Dear student,

$a) N a_{2} C O_{3} + H C l \to N a C l + N a H C O_{3} b) N a H C O_{3} + H C l \to N a C l + H_{2} O + C O_{2} c) 2 C u S O_{4} + 4 K I \to C u_{2} I_{2} + I_{2} + 2 K_{2} S O_{4}$

Regards

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Similar questions

Write the balanced chemical equations for the following reactions-

(a) Sodium carbonate on reaction with hydrochloric acid in equal molar concentration gives sodium chloride and sodium hydrogen carbonate.

(b) Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.

(c) Copper sulphate on treatment with potassium iodide precipitates cuprous iodide $({Cu}_{2} I_{2})$ , liberates iodine gas and also forms potassium sulphate.

Write the balanced chemical equations for the following reactions:

Sodium hydrogen carbonate on reaction with hydrochloric acid gives sodium chloride, water and liberates carbon dioxide.

Write the balanced chemical equations for the following reactions.

Sodium carbonate on reaction with hydrochloric acid in equal molar concentrations gives sodium chloride and sodium hydrogen carbonate.

Write the balanced chemical equations for the following reactions.

Copper sulphate on treatment with potassium iodide precipitates cuprous iodide

(C u I)

, liberates iodine gas and also forms potassium sulphate.

Q. Copper sulphate on treatment with potassium iodide precipitates cuprous iodide, liberates iodine gas and also forms potassium sulphate. Write a balanced equation for the mentioned reaction.

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Dear student, a) Na2CO3 + HCl →NaCl + NaHCO3b) NaHCO3+HCl →NaCl+H2O +CO2c) 2CuSO4 + 4KI → Cu2I2 + I2 + 2K2SO4 Regards

Dear student,

$a) N a_{2} C O_{3} + H C l \to N a C l + N a H C O_{3} b) N a H C O_{3} + H C l \to N a C l + H_{2} O + C O_{2} c) 2 C u S O_{4} + 4 K I \to C u_{2} I_{2} + I_{2} + 2 K_{2} S O_{4}$

Regards